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Lets say I have a directory full of .md files all named various things. Lets say I wanted to prepend "test" to the front of each file name. So for example: file a.md, b.md, and c.md would become test - a.md, test - b.md, and test - c.md.

How would I accomplish this via command line?

0

7 Answers 7

91

One-liner that can be easily typed straight from the terminal:

for f in *.md; do mv "$f" "test - $f"; done

Or rewritten on separate lines instead using semicolons:

for f in *.md
do
    mv "$f" "test - $f"
done

Exposition

Syntax of for (in sh):

for NAME [in WORDS ... ] ; do COMMANDS; done

Here, our NAME is f and our WORDS are all files in the current directory matching *.md. So the variable $f will be be substituted with each file matching *.md.

So for a.md:

mv "$f" "test - $f"

becomes

mv "a.md" "test - a.md"

The quotes are important because the each filename $f might contain spaces. Otherwise mv would think each word was a separate file. For example, if there were no quotes, and there's a file called Foo Bar.md, it would translate as:

mv Foo Bar.md test - Foo Bar.md

which would not work as intented. But by wrapping $f in quotes, it makes sense:

mv "Foo Bar.md" "test - Foo Bar.md"

Noting the syntax of for, you could also rename a subset of all the *.md files by naming each explicitly:

for f in a.md b.md d.md; do mv "$f" "Test - $f"; done

Or using shell expansion:

for f in {a,b,d}.md; do mv "$f" "Test - $f"; done
3
  • This is exactly what I needed to see. Thanks!
    – Ryan
    May 19, 2016 at 16:10
  • Great, served well for renaming all files to have .yaml extension, for f in ./*; do mv "$f" "$f.yaml"; done Jul 31, 2020 at 12:40
  • Great, thanks! For appending to the end of a filename but before the file extension, I did: filename="${f%.*}"; mv "$filename.md" "$filename textToAppend.md" inside the loop. I made use of this answer: stackoverflow.com/q/965053/17616747
    – David
    Dec 27, 2022 at 0:14
11

If you have prename...

prename 's/^/test - /' *.md

Using ordinary shell commands:

for file in *.md; do
    mv "$file" "test - $file"
done
2
  • How do I get prename ?
    – Gaʀʀʏ
    Nov 17, 2016 at 2:49
  • Seems to be preinstalled for me on Ubuntu 16.04 LTS. Have you tried your package manager (ie., sudo apt-get install)?
    – Orion751
    May 26, 2018 at 2:19
7

mmv1,2 is also a very nice tool for such a task, applied to the current job, it would be

mmv '*.md' 'test - #1.md'

Of course, if you only want to add "test - " to a.md, b.md and c.md, but not a1.md, something like

mmv '?.md' 'test - #1.md'

would be more appropriate.

I can really suggest it, especially if you have many such problems.

If you are additionally looking for a graphical interface, try gprename.

6

Instead of using a for loop, which will fail on spaces unless you redefine the IFS variable, I would recommend using a while loop combined with find. The following will work when run from the same directory as the files

find . -maxdepth 1 -type f -name '*.md' | while read -r file; do
    file=$(basename $file)
    mv "$file" "test - $file"
done

the "basename" line is in there so that find will print the file name only - without path components which would make the rename operation break.

2
3

I know it's really late, but if anyone else is looking for something like this, then this worked for me:

rename '' 'name -' *.md
1
  • 1
    simple and straight-forward
    – user13743
    May 15, 2019 at 2:42
0

If you have zsh available you could use zmv:

autoload zmv
zmv -w '*' 'test - $1'

You can test the command with:

zmv -wn '*' 'test - $1'
  • -n means dry-run, i.e. only show what will happen.
  • -w implicitly puts parenthesis around wildcards, makes backreferences work.
0

In bash, adding "Prepend text - " to all files in folder:

for i in *; do mv "$i" "$(echo $i | sed 's/^/Prepend\ text\ \-\ /')"; done;
1
  • This is a super-long way of writing for i in *; do mv "$i$" "Prepend text - $i"; done May 4, 2016 at 7:20

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