I have a unique situation where I need the following folder structure (Windows)
X:\LOGS\PRIMARY\YEARMONTHDAY
e.g.,
X:\LOGS\HS\20121010
Folders are created every morning.
Essentially I'd like to zip the contents of the date subdirectory and place it within that directory. Should this be done with 7z or with 'FORFILES'?
If I understand correctly, you want to take a specific folder that is created in a YYYYMMDD format and zip up the contents. The generated zip file needs to be placed in this folder as well.
At the most basic level you can accomplish this with a command like the following
"c:\Program Files\7-Zip\7z.exe" a x:\Logs\HS\20121010\20121010.zip X:\Logs\HS\20121010\*
NOTE: 7-zip must be installed to use the above command
With the above command you would have to manually fill in the YYYYMMDD every time you want to zip up a new date folder.
This can be taken a step further and you can modify the command to use the current YYYYMMDD for today's date. The key to this is to use the %date% variable in DOS. You can read more information about this variable by typing set /?. To format the date as YYYYMMDD we will need to take a sub-string of the %date% variable like so:
echo %date:~10,4%%date:~4,2%%date:~7,2%
The above command should output the date in YYYYMMDD.
Last we can put these two commands together to generate a one line command that will zip up all the files in the directory with today's date (in YYYMMDD format).
"c:\Program Files\7-Zip\7z.exe" a x:\Logs\HS\%date:~10,4%%date:~4,2%%date:~7,2%\%date:~10,4%%date:~4,2%%date:~7,2%.zip X:\Logs\HS\%date:~10,4%%date:~4,2%%date:~7,2%\*
One additional step can be taken to automate this by adding the above command as a scheduled task in windows.
