0

I have a folder in my server which contains some files. These are automated that means everyday we get new files automatically which will overwrite the old ones. So want to take a back up for this data. How can i copy all these files in to a another folder by renaming the files with current date while copying.

ex : i have a folder named folder1 which contains 4 files. path for this folder is home/install/project1/folder1

aaa.dat
bbb.dat
ccc.dat
ddd.dat

now i want to copy all these four files in to a different folder named folder2. path for this folder is home/install/project1/folder2. while copying these files i want to rename each file and add the current date to the file. so my file names in folder2 should be..

aaa091012.dat
bbb091012.dat
ccc091012.dat
ddd091012.dat

I want to write a Linux shell script for this. Please give me some idea or some sample scripts related to this.

6
  • @JimGarrison, i tried this command...$ mv /directory_one/* /directory
    – G M Ramesh
    Mar 4, 2013 at 5:47
  • @JimGarrison, for unix shell , i know the script how to copy files but for linux i dont know... if the unix commands works for linux also then its ok. i can make it out...
    – G M Ramesh
    Mar 4, 2013 at 5:49
  • 2
    98% of Unix commands have identical or very similar counterparts in Linux.
    – Ex Umbris
    Mar 4, 2013 at 5:52
  • @GMRamesh: which linux flavor are you using? Ubuntu?
    – mvp
    Mar 4, 2013 at 5:54
  • I am using Red Hat
    – G M Ramesh
    Mar 4, 2013 at 5:57

3 Answers 3

2
srcdir="home/install/project1/folder1"
dstdir="home/install/project1/folder2"
d=$(date +%m%d%y)

for srcfile in ${srcdir}/*
do
    dstfile=$(basename $srcfile)
    dstfile=${dstfile/\./${d}\.}
    cp $srcfile $dstdir/$dstfile
done
5
  • 1
    There are a few problems with that script; most notably, $srcfile will actually just be equal to $srcdir.
    – ruakh
    Mar 4, 2013 at 6:19
  • Good catch @ruakh, editing now
    – maverick
    Mar 4, 2013 at 6:20
  • Just add a note that this script would not copy any files present in sub-directories of srcdir to ensure it is what OP expects.
    – Tuxdude
    Mar 4, 2013 at 6:21
  • Now $dstfile will be e.g. home/install/project1/folder1/aaa091012.dat, so $dstdir/$dstfile will be e.g. home/install/project2/folder2/home/install/project1/folder1/aaa091012.dat.
    – ruakh
    Mar 4, 2013 at 6:23
  • Nice, @ruakh - edited again
    – maverick
    Mar 4, 2013 at 6:26
1

You can do it in 2 steps, first cp:

cp -rp source/ target/

Then use rename. But you should use Ubuntu flavor of it, which is actually Perl script. For Redhat, you might be able to install or download it from https://metacpan.org/module/rename. Unfortunately, native Redhat/Fedora rename does not support Perl regular expressions and will not work for this.

At any rate, use Perl-ish rename like this:

cd target
rename 's/\.dat$/091012.dat/' *

You can even use it recursively by combining it with find and xargs, something like:

find | xargs rename 's/\.dat$/091012.dat/'
0

this worked for me:

    cd home/install/project1/folder1
    for f in *.dat
    do 
    cp -v $f /home/install/project1/folder2/${f%.dat}$(date +%m%d%y).dat
    done

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .