Find out the depth of path in PowerShell

Question

For any location gotten by the Get-Location cmdlet, if I have a path like this:

C:\Top\Middle\Bottom

I would say it's 3 levels deep.

If I have:

C:\

I would say it's the 0 level. It could be 0 or 1 but the logic of depth is what matters.

Is there a way to figure this out?

soandos · Accepted Answer · 2015-01-13 04:00:00Z

1

I think the simplest way of doing this (assuming that your files do not have a \ in their names) is like:

$file.FullName.ToString().Split('\\').Count

answered Jan 13, 2015 at 4:00

soandos

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In my case it'd be (Get-Location).Path.ToString().Split('\\').Count right? It gives 2 for both C:\ and C:\Top. For all deeper levels it works fine.
– laggingreflex
Jan 13, 2015 at 4:04
@laggingreflex I think thats correct. If you want you can special case drive letters only if you want (length will be three, and those are always drive letters)
– soandos
Jan 13, 2015 at 4:14

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music2myear · Accepted Answer · 2019-05-21 15:38:34Z

-1

This code:

((Get-Location).Path.ToString().Split('\\') | ? {$_ -ne ""} ).Count

Returns 1 for c:\

Returns 2 for c:\users\

music2myear

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answered May 21, 2019 at 13:55

Scholtz

1011 bronze badge

(Get-Location).Path.TrimEnd('\').split('\').count
– Keith Miller
May 21, 2019 at 17:27

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2 Answers 2