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I am using Dropbox, and I wind up with a number of files like:
prefs (home's conflicted copy 2009-07-20).js

What I would like to do is find all the "conflicted copy..." files and then compare each with its unconflicted version.

For example, the following command gives me the result:

$ find . -name "*onflict*" -exec ls -ld {} \;
-rw-r--r-- 1 eric eric 24203 2009-07-19 14:42 ./prefs (home's conflicted copy 2009-07-20).js

but I would like an output like:

-rw-r--r-- 1 eric eric 24429 2009-07-21 11:43 prefs.js
-rw-r--r-- 1 eric eric 24203 2009-07-19 14:42 prefs (home's conflicted copy 2009-07-20).js

and then I can decide what I want to do with the conflicted copy. Any ideas?

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up vote 2 down vote accepted

I figured out something that seems to works, but I would welcome suggestions to improve it, including making it cleaner:

find . -name "*onflict*" | while read name; do ls -ld "$name"; ls -ld "${name/ (*onflict*)/}"; echo -n "$name" | xargs -0 -p rm ; echo ; done

In a more easily read and typed format:

find . -name "*onflict*" | \
while read name; do 
    ls -ld "$name"
    ls -ld "${name/ (*onflict*)/}"
    echo -n "$name" | xargs -0 -p rm 


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After you've matched the conflicted filename, use a regular expression to replace the parenthesis and space with a star and do, for example:

ls -d "prefs*.js"
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BTW, the example ls -d "prefs*.js" is an example of shell filename expansion or shell pattern matching, functionality which is a subset of full regular expresions. – pcapademic Jul 21 '09 at 23:22
But how do I apply regular expression to the {} in the find command -exec option? – pcapademic Jul 21 '09 at 23:34
You might want to write a perl version of this instead, but I bet it could be written with just a single line using awk/sed, I'm just not proficient enough to describe it. – Stefan Thyberg Jul 21 '09 at 23:50

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