Super User is a question and answer site for computer enthusiasts and power users. It's 100% free, no registration required.

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

How to sort a file using sort command..

I would like to sort the file based on 2nd field which is seperated by "," as a delimiter

Ex: filename1, 465, output_file1,

filename2, 300, output_file2,

Expected output :

filename1, 300, output_file,

filename1, 465, output_file,

I tried this command

sort -t, +1 -2 <file.txt>

But this didn't help. Please let me know if I am missing something

thanks Kiran

share|improve this question

migrated from Feb 23 '10 at 13:22

This question came from our site for professional and enthusiast programmers.

GNU sort:

sort -t, -k2 -n file.txt
share|improve this answer
Thanks, It worked. – Kiran Feb 23 '10 at 9:09
@Kiran : please mark the answer as accepted, then :) – Valentin Rocher Feb 23 '10 at 9:21

You should use sort -t, -nk 2 -s file.txt

-n specifies it as numeric sort and -k specifies key to be used for sorting The +1 etc., options are not supported now.

share|improve this answer

Adding -k 2 to specify field 2 should do it:

sort -t , -k 2 $file

Not sure what +1 -2 comes from. Also, this should probably be on

share|improve this answer

The command below will do it for you, nice and simple :-)

sort -t, -k 2n,2 t.txt

share|improve this answer

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.