What is the weight of a gigabyte of memory? Lets say this is on a hard disk. What is the weight associated with the atoms that are actually storing the data on the disk?

How has this value changed as densities of disks have increased?

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The answer is 7x. I'll leave determining the value of x as an exercise for the reader. – Pesto Jul 23 '09 at 13:54
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Callum: I can't tell yet whether you are just acting dumb or actually have no idea what you are talking about. – TheTXI Jul 23 '09 at 14:30
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@TheTXI: I really don't think it is an act. – Geoffrey Chetwood Jul 23 '09 at 14:32
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jamuraa: That is even worse, seeing as how the space required to store a gigabyte is constantly shrinking...which is how we managed to go from storing 1GB to 1.5TB without having to constantly build bigger pc cases and drive enclosures. – TheTXI Jul 23 '09 at 14:54
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jamurraa: If you feel like posting an explanation on the size (area) required to take up one GB, feel free. And feel free to come back here twice a year and edit your post to make sure it is accurate. – TheTXI Jul 23 '09 at 15:13
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closed as not constructive by Tom Wijsman, random Sep 8 '11 at 3:28

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9 Answers

up vote 29 down vote accepted

Hard drive density is measured in bits per square inch, the maximum of which is currently (5/2011) 625 gigabits per square inch. This means that a gigabyte of data will take up about 8.25 millimeter2. The weight of the substrate (usually glass and ceramic) and the magnetic layer which actually holds the magnetic grains. The magnetic layer is usually made of a mostly cobalt alloy of 10-20 nm thickness. Assuming 10nm thickness to make the math easier, This gives us about 8.25 * 1013 nm3 of magnetic layer material for one gigabyte.

Given the density of cobalt, this means that we can approximate the weight at 0.734966 micrograms.

I'm not sure how much the substrate weighs, but it's almost certainly more than that.

Previously on "How much does a gigabyte weigh on a hard disk?"

  • 2009: Areal Density 400 Gbit/in2 = 1.1518 micrograms (ref)
  • 2010: Areal Density 541.4 GBit/in2 = 0.84817 micrograms (ref)
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sorry about the original bad numbers, my area calculation was off by a bit (okay, WAY off) – jamuraa Jul 23 '09 at 15:47
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I now feel like crying and slamming a car door on my face. – TheTXI Jul 23 '09 at 15:56
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Remember to come back twice a year and update your answer now jamurra! – Callum Jul 23 '09 at 16:22
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+1 for the consistent updates alone. I'd upvote every year if I could. – Daniel Beck Jun 3 '11 at 11:25
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Wow so you actually have come back for the last two years and edited this... now that's dedication +1 – Kyle Jun 3 '11 at 11:48
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The data kept on a disk does not increase the weight of the disk. The only weight differences in disks would be in the overall size of the disk (example: regular HDDs are larger than laptop HDDs in terms of size and typically mass, and larger sized disks can have more platters to hold data than older ones) itself and in the materials used to make the disk.

Data is stored by switching the magnetic polarity on the disk, not by adding or subtracting something from the actual substance. A full disk will have the same mass and will therefore weigh the same (assuming you don't move the disk to a location where gravity is stronger or weaker, such as the moon).

Switching the polarity of a hard disk is like turning a magnet around so that the north and south poles are switched. It is not analagous to creating an ion (removing or adding electrons of an atom to give it a positive or negative charage). That could theoretically adjust the mass of the disk, but for all intents and purposes electrons do -not- have mass (so infinitesimally small that it almost appears so at least), so you are back to square one again if the disk did somehow operate in this manner, which it does not.

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Good answer to a rubbish question. Reminds me of a DBA I once worked with who suggested that we install the software on the servers after we moved them so they wouldn't be too heavy. He was being serious. Put me off DBAs for about 6 years. – Jon Hopkins Jul 23 '09 at 14:26
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On the disk an individual bit weighs nothing, it's just a change in magnetic polarity; see TheTXI's answer for a more elaborate explanation of this.

In RAM, however, bits are comprised of electrons (or lack thereof) and they do have a mass which is about 9.10938215 × 10−31 kg. So for a GiB of memory, assuming equal distribution for zero and one bits, we get around

4294967296 n × 9.10938215 × 10−31 kg

4294967296 would be the number of one bits in memory (assumed to be 50 %) and n would be the number of electrons that are on average in one bit. I have found one source1 that specified this number at around 105.

So we can give an estimate of how much mass 1 GiB (or 1 GB) of memory would have:

1 GiB, half filled with ones ≈ 3.91 × 10−16 kg = 391 femtograms

1 GiB, completely filled with ones ≈ 7.82 × 10-16 kg = 782 femtograms

1 GB, half filled with ones ≈ 3.64 × 10−16 kg = 364 femtograms

1 GB, completely filled with ones ≈ 7.29 × 10−16 kg = 729 femtograms

So in general you can assume that weight to be pretty unnoticeable (or, with hard disks to be downright nonexistant).


1 These lecture slides, but they are in German.

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+1 for the RAM explanation. – TheTXI Jul 23 '09 at 14:50
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Trivia to add: On researching the numbers for this I stumbled over a fun calculation which estimated the mass of traffic on the internet at a single point in time to be roughly equivalent to the mass of a grain of sand. – Joey Jul 23 '09 at 14:52
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Not-serious answer

It depends on what font size your text is saved in. 24-point font is very heavy, whereas 8-point is quite light. Bold text also increases the weight, and you should avoid saving lots of text in italics, because all the characters lean to the right, which changes the way the disk spins.

Serious answer

Data has no mass.

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That sounds like something out of Dilbert. Actually, now that I think about it, I'm almost sure I've seen something about bold text weighing more. – mmyers Jul 29 '09 at 18:40
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I would say 42.

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+1, definitely 42 – Olivier Payen Jul 23 '09 at 14:29
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The correct answer is 0. He didn't ask how much hard drive does it take to store 1 GB, he asked how much 1 GB weights on a hard disk. As we know it uses magnetic storage and not an electrical charge (which would weigh something), then correct answer is 0.

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It depends on the data.

Yes, hard drives store data by flipping poles in magnetic domains on the disk--at first glance this means nothing is added or subtracted and thus no weight.

However, that's not the whole picture. The orientation of those domains matter. There is less total field energy when the domains are 1010101010 than when they are 11111111 or 00000000. I'm sure everyone is familiar with e=mc^2. Putting energy into the domains DOES mean mass, albeit an incredibly small amount of it.

My physics isn't up to even trying to estimate the mass but I'm sure it's beyond anything the most sensitive scale could possibly measure.

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Indeed, you're talking about less than a trillionth of a gram, though it depends highly on the storage medium. I did a blog post about it once (and thought I'd leave a note here for interested readers). – David Zaslavsky Nov 1 '11 at 2:38
@David Zaslavsky: I'm surprised it's that much. – Loren Pechtel Nov 1 '11 at 3:05
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Depends on where you're doing the weighing. One of the answers immediately jumps into discussing femtograms, which are not a measure of weight, but instead measure mass.

On the moon things weigh less, on Jupiter they weigh more. In space they weigh nothing.

So, the answer is ... depends.

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I wonder which bottle all you smartasses come from. The question was simple: how many gigabytes of information can you store per kilogram of storage media with current technology?

Example: http://www.myddnetwork.com/new-gadgets/pqi-h566-usb-external-hard-drive-first-3-0-ready-2-5-inch-portable-unit/ where 640GB / 200g = 3200 GB/kg

Relevant question. Now we just need someone to collect the historical data and plot it.

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