Unix 'grep' for a string within all gzip files in all subdirectories

Question

How do I grep for a string recursively through all .gz files in all directories and subdirectories?

Answer 1

@Steve Weet is almost there. The use of /dev/null as an additional argument is a nice way to force the filename to be shown (I'll remember that, thanks Steve) but it still runs the exec for every file found -- a huge overhead.

You want to run zgrep as few times as you can, getting the most out of each execution:

find . -iname '*.gz' -print0 | xargs -0 zgrep PATTERN

xargs will supply as many args (filenames) as possible to zgrep, and repeatedly execute it until it has used all the files supplied by the find command. Using the -print0 and -0 options allows it to work if there are spaces in any of the file or directory names.

Answer 2

$ zgrep --help
Usage: /bin/zgrep [OPTION]... [-e] PATTERN [FILE]...
Look for instances of PATTERN in the input FILEs, using their
uncompressed contents if they are compressed.

So something like

find . -iname "*.gz" -exec zgrep PATTERN {} \

Answer 3

@aioobe is almost there. The command will do the job but won't tell you the file name

The following should tell you the filename as well:

find . -iname "*.gz" -exec zgrep PATTERN {} /dev/null \;

The addition of /dev/null will ensure that zgrep sees two filenames so it will show you the name of the file if it finds the string

EDIT

Further research reveals that for my machine (OS/X) the -exec argument to find will add as many filenames as possible (similar to the way xargs behaves).

Answer 4

The following works a treat in zsh

for archive in **/*.gz; do
    echo "[${archive}] "
    gzip -dc ${archive} | grep -n "String"
done

It may also work in bash, ksh, etc...