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This is something I do frequently

$ mkdir foo
$ cd foo

This works as a single command, but it's more keystrokes and saves no time.

$ mkdir foo && cd foo

Is there a shortcut for this?

Edit

With the use of help below, this seems to be the most elegant answer.

# ~/.bashrc
function mkcd {
  if [ ! -n "$1" ]; then
    echo "Enter a directory name"
  elif [ -d $1 ]; then
    echo "\`$1' already exists"
  else
    mkdir $1 && cd $1
  fi
}
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You can rename the function to mkdir if you use command mkdir $1 instead of just mkdir $1 in the function body. –  Andy Jun 15 '10 at 14:50
1  
(1) why not simply "mkdir $1 ; cd $1" instead of "&&"? that way the "cd" succeeds even if the "mkdir" fails, and you don't need the does-it-already-exist scaffolding. (2) as written your function won't work (to prompt you for a directory name). you need to put that in a separate "if" clause from the existence test (currently in "elif"). –  quack quixote Jun 15 '10 at 16:25
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5 Answers 5

up vote 8 down vote accepted

I'm no Linux/bash expert, but try putting this in your .bashrc.

function mkdir
{
  command mkdir $1 && cd $1
}

PS Thanks to Dennis for using command mkdir.

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Instead of `which mkdir`, just use command mkdir. –  Dennis Williamson Jun 15 '10 at 14:33
    
Thanks Dennis. There's nothing under man command - could you direct me to a reference? (I can work out what it does, but it pays to be thorough;) –  Andy Jun 15 '10 at 14:49
1  
command is described in the manual of bash (which it is a built-in of; it's not a separate command). You could also try help command. –  grawity Jun 15 '10 at 18:39
    
@grawity Perfect, thanks. –  Andy Jun 16 '10 at 8:04
2  
Not sure why this is not the accepted answer—the currently accepted one doesn't even seem to work. –  Erik Allik Oct 13 '13 at 16:18
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If you don't want another function to remember and don't mind bashisms:

$ mkdir /home/foo/doc/bar && cd $_

The $_ (dollar underscore) bash command variable contains the most recent parameter. So if a user were to type the following at the command line: echo foo bar && echo $_ baz, then the output would be as follows:

foo bar
bar baz
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2  
This works in zsh too. –  Nabil Kadimi Feb 16 at 10:01
1  
Can you explain what $_ is? Newbie here. –  arg20 Jun 25 at 15:16
1  
@arg20 I updated my answer. –  kzh Jun 25 at 18:04
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You can try something like this:

#!/bin/sh
mkdir $1 && cd $1

Save this script to some place that is in your path, for example, /usr/local/bin or ~/bin (you have to put this last one into your path in your ~/.profile file). Then you can simply call it.

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2  
how can this work? it seems to only cd inside the context of the execution of the ~/bin/mkcd script, not the caller of the script. –  Erik Allik Oct 13 '13 at 16:15
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What about:

$ mkdir newdirname; cd $_

It's a bit easier than using &&, combining quack quixote's and kzh's answers.

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10  
The point of && is that cd will not be executed if the mkdir command fails –  slhck Mar 14 '12 at 9:29
    
@slhck actually that was the point of quixote: cd even if mkdir fails (for instance if it already exists, forcing the user to write a second command to actually cd to the path). However contrarily to what this answers says, that's not for easiness: && is not more complicated than ;. –  moala Feb 2 '13 at 9:13
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$echo 'mkcd() { mkdir -p "$@" && cd "$_"; }' >> ~/.bashrc
$mkcd < pathtofolder/foldername >
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