Batch script to launch an application

Question

I've a simple batch script npp.bat to open a file in Notepad++

"C:\Program Files\(x86)\Notepad++\notepad++.exe" %1

Notepad++ launches with the file when I run npp <file_name&gt> but the command window waits for the application to exit. I don't want it to wait.

Answer 1

Use start instead:

start "" "command here"

Edit: Do not miss the first pair of empty quotes, this is the title of the process/window.

start <title> <command> <parameters>

See start /? for further details.

Answer 2

I wanted to be able to do "npp file.txt" on the command prompt and be able to edit files using Notepad++. For this, I created a new folder, added it to Windows PATH, and created a file there called npp.bat with the following content:

@echo off
start "" "C:\Program Files\Notepad++\notepad++.exe" %1

Very useful when I'm working on the console and need to edit a file.

Answer 3

@Bobby method should work, If you directly calls the batch script ( double click ), the method will open a new command window. Instead use the following,

@echo off
start "C:\Program Files\Notepad++\notepad++.exe" blah.txt
cls
exit

If you replace blah.txt with %1, then you should pass the argument when you call the batch file.