Run a file on startup in Linux

Question

I have a Python script that I would like to have run on startup in Ubuntu. Is there an easy way to do this?

Answer 1

This was answered here:

http://stackoverflow.com/questions/3036/linux-files-and-scripts-that-execute-on-boot

Answer 2

In Ubuntu, the recommended method of doing this is to use Upstart. In order for this to work, you must create a job file placed in:

/etc/init

The exact structure of the script, can be found at:

http://www.linux.com/archive/feature/125977?theme=print

A brief example, however, could look like this:

start on runlevel 2
script
   echo "Started"
end script

In this example, when the system switches into runlevel 2, upstart will emet a "runlevel 2" event. All jobs in the /etc/init directory which have a start or stop trigger for runlevel 2 will run. This script is triggered to start on this event, and will do so by echoing "Started". It then exits the script, and will run again the next time the system enters runlevel 2.

A decent tutorial can also be found here:

http://www.linuxplanet.com/linuxplanet/tutorials/7033/1/

Answer 3

I would suggest using a cronjob for it. There is a scheduling event to run on startup.

Answer 4

That's what rc.d is for.

http://www.linux.com/news/enterprise/systems-management/8116-an-introduction-to-services-runlevels-and-rcd-scripts

Answer 5

You could create an init.d script UbuntoBootupHowto

Answer 6

Create a file rc.local and chmod it to make it executable, then stick in the python script

#!/bin/sh
python_cmd

The usage of rc.local is distribution dependent, it may be in /etc/init.d or in /etc/rc.d/