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When I work with the JDK, it says that javac is not recognized as an internal or external command. What shall I do? What is the path for jdk1.6.0_21?

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I am running Windows 7 Ultimate 64 bits SP1. I installed jdk_7u4_windows_x64.exe - that is Java SE Development Kit 7 update 4 in 64 bits and Java FX 2.1 SDK. file location is c:\windows\system32\java.exe (185KB size) the folder path is c:\program file\java\jdk1.7.0.0_04 I also go to control panel/system/advance system setting/advance/environment variables/new variable name = JAVA_HOME variable value = c:\windows\system32\java.exe I download Android SDK installer_v18_windows.exe for windows 7 x64 bit and run, refused: Java SE Development kit (JDK) not found Still unable to install SDK so far. I – young707 May 18 at 22:03
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Depending on if you installed the 64-bit or 32-bit JDK it should be in:

  • 32-bit: C:\Program Files (x86)\Java\jdk1.6.0_21\bin
  • 64-bit: C:\Program Files\Java\jdk1.6.0_21\bin

You should be able to edit your PATH environment variable to include that path.

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Well, went back, uninstalled all the JDK entries in control panel.

  • Load Java SE Development Kit 7 update 4 for Windows x 86 (32 bits) jdk-7u4-windows (even we are running Windows 7 Ultimate x64 bits SP1 system.)

  • Install this 32 bits JDK kit in c:\program files (x86)java\jdk1.7.0_04\

  • For the Android installation download installer_r18_windows.exe, then locate the Java SE folder at c:\program files (x86)\java\jre7\bin\java.exe

Conclusion: SDK only know the 32 bits JDK folder location even we are running Win 7 64 bit systems. The Program Files folder locations are different.

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