Take the 2-minute tour ×
Super User is a question and answer site for computer enthusiasts and power users. It's 100% free, no registration required.

I got a hp laser jet 3050 printer,which is connected to the internet and shared by a group of people,and it works well with other people.But while i am trying to install it under my xp system,problem came out--I need the ip address of this printer.I have tried to let the printer print the infomation out itself,but i failed(there are 'Usage page','Service Page','Self Test/Configuration Page',but none of them have the ip info i needed).So does anybody got any idea about what should i do? thanks a lot.

share|improve this question
    
Hmmm, I'm stumped. I don't have the printer, but the manual makes it look like you have to configure the IP from the PC, which is strange if you don't yet know the IP! –  Azz Oct 10 '10 at 14:45
    
@Azz (In those situations, I believe setup programs send a special broadcast message on the local subnet to find the IPs of all matching devices.) –  Bavi_H Oct 11 '10 at 1:54

1 Answer 1

On the printer, press the menu/enter button, press arrow to the right to "reports", press the menu/enter button, press arrow to the right to "usage", press menu/enter button.

The printer should automatically print a self-test/configuration page, where I believe the IP address is included.

share|improve this answer
    
The manual suggests you print the Config report from the Reports menu to find the IP address. (See HP LaserJet 3050 User Guide → How do I? → Network → Set up the all-in-one and use it on the network.) –  Bavi_H Oct 11 '10 at 1:28
    
thanks for your answer,i have tried again step by step exactly by your instruction.But the IP address is not included indeed. –  david zhu Oct 12 '10 at 10:52
    
Did it print one or two pages? –  harrymc Oct 12 '10 at 16:44

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.