What regular expression can I use to match an IP address?

Question

With the following grep syntax I want to match all IP address in a file (from a ksh script)

  grep '[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}' file

The problem: It also matches words (IP) that have more then 4 octets:

1.1.1.1.1 

or

192.1.1.1.160

How can I match a valid IP and only IP addresses with 4 octets? I can also use Perl – a one line syntax solution, if grep doesn't work.

Answer 1

try this:

grep -E '[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}' /etc/hosts

which matches all expressions from 0.0.0.0 to 999.999.999.999

with

grep -Eo '[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}' /etc/hosts

you will get IP addresses only

note:
on solaris probably egrep will do the job.

Answer 2

How's this:

perl -MRegexp::Common=net -ne '/($RE{net}{IPv4})/ and print "$1\n"' /etc/hosts

Answer 3

if [ ` echo $ip | '^((25[0-5]|2[0-4][0-9]|[01]?[1-9][0-9]?)\.){3}(25[0-5]|2[0-4][0-9]|[01]?[1-9][0-9]?)$'  | grep -o "\." | wc -l` -eq 1 ];
then ipv4=true;
else 
ipv4=false;

Answer 4

A little tricky, but it should work:

( X='\([0-9]\{1,2\}\|1[0-9]\{2\}\|2[0-4][0-9]\|25[0-5]\)' ; grep "\([^\.]\|^\)$X\.$X\.$X\.$X\([^\.]\|$\)" file )

Answer 5

The

-w / --word-regexp 

flag to grep makes it only match on word boundaries, meaning that your match must either be surrounded by whitespace or begin / end at the beginning / end of the line!

Answer 6

To only find matches with 4 octets exactly (excluding things like 1.1.1.1.1) use this:

grep -P '(?<=[^0-9.]|^)[1-9][0-9]{0,2}(\.([0-9]{0,3})){3}(?=[^0-9.]|$)'

It should never detect non-IP-addresses. The expression could be more complex to verify more things but this should work for most cases. It will not match a preceding 0 since 010.1.12.1 is not a common way to write IP addresses.