How to check if a directory exists in Windows?

Question

I would like to translate this Linux/Bash script to Windows shell:

if test -d myDirName; then echo "ok"; else mkdir myDirName; fi

It tests if a directory exists, and if it doesn't it creates it.

Answer 1

@echo off
IF exist myDirName ( echo myDirName exists ) ELSE ( mkdir myDirName && echo myDirName created)

Answer 2

Here is what I just found out:

You can test if a nul file exists; if the directory exists it will contain a nul file, if the nul file does not exist then the directory does not exist.

IF exist myDirName/nul ( echo myDirName exists ) ELSE ( mkdir myDirName && echo myDirName created)

Answer 3

Use a backslash, not forward slash: myDirName\nul not myDirName/nul

md foo 
echo.>bar 
for %I in (foo bar xyz) do @( 
  if exist %I ( 
    if exist %I\nul ( 
      echo -- %I is a directory 
    ) else ( 
      echo -- %I is a file 
    ) 
  ) else ( 
    echo -- %I does not exist 
  ) 
)

-- foo is a directory
-- bar is a file
-- xyz does not exist

Answer 4

exist myDirName/nul

also is true if myDirName is a file, whis is not the searched functionality