How to delete multiple users?

Question

How to i implement deletion of multiple users in my code. So i have an option as an admin to delete multiple users in 1 command

#!/bin/bash
echo "SELECT $OPTION"   
echo "-------------"   
echo "1- Create username"   
echo "2- Create password"   
echo "3- Delete username"   
echo "4- Exit"   
read -p "enter option 1 2 3 or 4:" option   
case $option in      
1) read -p "Enter username:"        
 adduser $REPLY && echo "Username successfully entered"   ;;      
2) passwd && "Password successfully entered" ;;      
3) read -p "Enter user to be deleted: "         
deluser $REPLY && echo "User deleted"  ;;      
4) exit  ;;         
esac

I got this code to delete multiple users

 read -p "Enter users to be deleted: "  #whitespace-separated list of usernames to be deleted     
 for USER in $REPLY; do         
  deluser $USER && echo "User $USER deleted"       
 done;;

But how do i implement this in my code, do i use a while loop, can someone tell me what i need to do.

Thank You

Answer 1

You need to add another option and insert your code in the case statement.

But, first I'd recommend that you read up on bash scripting.

Here is the only link you'll (ever) need: http://tldp.org/LDP/abs/html/

Regards, jgr

Answer 2

The read and for loop can be included in the case statement just as you show it. Here, I show it as a replacement for case 3.

case ...
...
3) read -p "Enter users to be deleted: "  #whitespace-separated list of usernames to be deleted     
    for USER in $REPLY; do         
        deluser $USER && echo "User $USER deleted"       
    done;;