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I'd like to somehow spit out a file (which has env variable references) and substitute the actual values. This is what I've tried, but as you can see it's not working. Any ideas?

-bash-3.00$ cat vars_file 
-bash-3.00$ export MY_VAR=MY_VALUE; cat ./vars_file | xargs echo
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4 Answers

up vote 4 down vote accepted

Old thread, but this is a recurrent issue. Here is a solution using bash's mapfile:

mateus@mateus:/tmp$ cat input.txt
a = $a
b = $b
mateus@mateus:/tmp$ echo a=$a, b=$b
a=1, b=2
mateus@mateus:/tmp$ function subst() { eval echo -E "$2"; }
mateus@mateus:/tmp$ mapfile -c 1 -C subst < input.txt
a = 1
b = 2

The bash builtin mapfile calls user-defined function subst (see -C/-c options) on each line read from input file input.txt. Since the line contains unescaped text, eval is used tu evaluate it and echo the transformed text to stdout (-E avoid special characters to be interpreted).

IMHO this is a much more elegant than any sed/awk/perl/regex based solution.

Another possible solution is to use shell's own substitution. This looks like a more "portable" way not relaying on mapfile:

mateus@mateus:/tmp$ eval echo "\"$(cat <<EOF_$RANDOM
a = 1
b = 2

Note we use EOF_$RANDOM to minimize conflicting cat's here-document with input.txt content.

Both examples from: https://gist.github.com/4288846

EDIT: Sorry, the first example do not treats comments and white space correctly. I'll work on that and post a solution.

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Can be done with script (e.g. file name is expand.sh):

while read line; do eval echo \"$line\"; done < $1 > $2

The script may be called like this:

env VAR1=value1 sh expand.sh input_file output_file


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any idea how to do this when there's a paren in the file? -bash: syntax error near unexpected token `(' –  andersonbd1 Jan 20 '11 at 17:51
@andersonbd1: I suppose you could replace the parentheses with sed and replace them back later. Otherwise, you might want to consider to remove the accept mark from my answer to get a better awk solution, as the above questions mentions that you can't read the effect with sed. –  Tom Wijsman Jan 20 '11 at 18:09
I guess sed is my best bet. It ain't pretty but it'll work. Thanks TomWij –  andersonbd1 Jan 20 '11 at 18:24
You might want to quote that variable: echo "$line". @andersonbd1: what is the context of the parentheses? –  Dennis Williamson Jan 20 '11 at 19:06
Oops, sorry, I forgot to say that you should use read -r, too. –  Dennis Williamson Jan 20 '11 at 19:14
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As described in the same thread at http://www.issociate.de/board/post/281806/sed_replace_by_enviroment_var_content.html, the "proper" solution would be as follows:

awk '{while(match($0,"[$]{[^}]*}")) {var=substr($0,RSTART+2,RLENGTH -3);gsub("[$]{"var"}",ENVIRON[var])}}1' < input.txt > output.txt

eval approach is fine, but tends to fail on XML files for instance.

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Here's my proposed solution:

eval $'cat <<\002\n'"$(<ifile)"$'\n\002' > ofile

\002 can be replaced with any character or string that doesn't occur in the ifile. To delete any occurrences of the delimiting character in the input file:

eval $'cat <<\002\n'"$(tr -d '\002' < ifile)"$'\n\002' > ofile

This solution seems to resolve most issues but is notably vulnerable to command injection in the template file through $(command) directives.

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