Take the 2-minute tour ×
Super User is a question and answer site for computer enthusiasts and power users. It's 100% free, no registration required.

Google just released a Chrome extension to block certain sites from its search results. Is there a similar solution for Opera 11?

share|improve this question
    
    
I'm also looking for this extension, and preferably with this feature too (from the above Google blog link): "If installed, the extension also sends blocked site information to Google, and we will study the resulting feedback and explore using it as a potential ranking signal for our search results.". –  galacticninja Feb 18 '11 at 8:34

2 Answers 2

up vote 0 down vote accepted

Not yet at least. Hopefully Opera will add this functionality, but I doubt it.

share|improve this answer
    
A shame. I've been trying to find a UserJS but haven't even found a repos that is up-to-date. –  HNoodles Feb 15 '11 at 14:17
    
@HNoodles Have you had a look at the related question ? There's a GreaseMonkey script which might work –  Sathya Feb 15 '11 at 16:41
    
Checked in out, it does not work with Opera. –  HNoodles Feb 15 '11 at 19:39

Google search results blocker

I've also been looking for such an extension but didn't find one. So I made one. At the moment it's fairly basic but seems to work. I'd appreciate any feedback either on the opera extension site or on the github page.

In terms of sending blocked search results to google, I'm not sure how much useful data that would provide given how few opera users there are compared to chrome. It would be nice though if blocked results automatically synced through your google account as with the chrome blocklist extension.

I'm also not entirely sure if the opera extension api exposes the features required to do this, but I haven't looked into it much.

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.