“command not found” when running a shell script. What did I break?

Question

I'm on OSX Snow Leopard.

Here's the full contents of grr.sh:

#!/bin/sh

echo wow

When I try to run it from terminal:

$ grr.sh
-bash: grr.sh: command not found
$ /bin/sh grr.sh
wow
$ sh grr.sh
wow
$ bash grr.sh
wow

Okay. Fair enough. I'll give it executable permission, then try again:

$ chmod +x grr.sh
$ grr.sh
-bash: grr.sh: command not found
$ chmod 755 grr.sh
$ grr.sh
-bash: grr.sh: command not found

Hmmm. Maybe it'll work if I use bash explicitly? I'll change the file's contents to:

#!/bin/bash

echo wow

And I get the exact same results. What could I have broken?!

One last thing! In case you're curious...

$ which sh
/bin/sh

Answer 1

Absolutely nothing. Only executables in one of the directories in $PATH can be run directly, and . is (usually) never in $PATH. Specify the path to the executable, i.e. ./grr.sh.

Answer 2

Is the location of grr.sh in the $PATH variable? If not, you'll need to enter:

./grr.sh

if you are in the same folder as grr.sh. If not, then provide the full path to it.

Answer 3

Yeah, and what ./grr.sh means, is that in this directory, run the command grr.sh. The single . means in the working directory. Otherwise, your shell assumes you are trying to run a command in your $PATH.