Super User is a question and answer site for computer enthusiasts and power users. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

I have a bunch of photos with varying names.
I want to give each photo a random name(*), how do I do that?

(*)I'm going to put them on a digital photo-frame that can't shuffle

share|improve this question
2  
Do you want a single solution that works for all of those platforms? Or a solution that works on any one? What script languages are you limited to or prefer? Are all the photos in one folder or multiple? – EBGreen Jun 30 '11 at 20:43
    
@EBGreen - I have a solution that works wherever bash is available. I would also like one that works on windows. (and recommending cygwin is cheating) – Nifle Jun 30 '11 at 20:51
    
Why not use the MD5 sum? – AngelLeliel Jun 30 '11 at 22:54
    
While MD5 sums would make name collisions less likely, MD5 collisions are a known issue. mscs.dal.ca/~selinger/md5collision – EBGreen Jul 1 '11 at 0:01
    
@Angel - Using the MD5 sum as a name would have worked pretty well for uniqueness. The extra time to calculate the sum on 4000+ photos would have been a boring wait. – Nifle Jul 2 '11 at 10:52
up vote 5 down vote accepted

Assuming all the images are in a single folder, this would work in powershell:

Get-ChildItem *.jpg | ForEach-Object{Rename-Item $_ -NewName "$(Get-Random)-$($_.Name).jpg"}

It is possible that you would get potential name collisions, but Get-Random by default returns a 32 bit unsigned int from 0 to Int32.MaxValue (0 to 2147483647). You could certainly add another Get-Random in to reduce the likelihood of a collision just as in the Bash answer.

share|improve this answer

One way if you have a bash shell handy is to use the $RANDOM environment variable. It generates random values between 0 and 32767.

A simple for loop in bash works fine if you only have a few hundred files.

for i in *.jpg; do mv -i "$i" ${RANDOM}.jpg; done

Since I had about 4000 files to rename I soon got collisions that the -i flag to mv caught. Adding another $RANDOM took care of that.

for i in *.jpg; do mv -i "$i" ${RANDOM}${RANDOM}.jpg; done
share|improve this answer
2  
Instead of "${RANDOM}${RANDOM}.jpg" you could also say "${RANDOM}-$i". This will avoid collisions and keep the old name information (as well as satisfy the random sort requirement). – bitmask Jun 30 '11 at 21:17
    
Oooh...I like it....I'll tweak the PS solution to incorporate that. – EBGreen Jun 30 '11 at 23:57
    
@bitmask - A good point. In this case the images didn't have any meaningful names and sometimes contained spaces so I was happy to get rid of them. – Nifle Jul 1 '11 at 8:46

for f in *; do ext=$(echo "$f" | sed 's|\([^.]*\)||'); mv "$f" "$(uuidgen)$ext"; done

share|improve this answer
    
+1 for showing me that uuidgen exists. – Nifle Jul 1 '11 at 8:48

Most batch file renamers can do this, here is one

Easy method would be to do a sequential numbering of the file, I am sure there other options with this software, use your imagination.

Here is the one I use for bulk renaming tasks

share|improve this answer

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .