x is an integer > 0
for x = 0, return 0; for all other x, return 1
solutions I have considered:
"IF(whatever)", obviously. Want to avoid it if possible, just cuz nested/lengthy formulas using them get messy.
"IFERROR(x/x, 0)"
Hey TBH I remembered the existence of "IFERROR()" just as I was writing this. That is probably the solution I'll use if no one posts anything better.
Just curious at this point.
TY!
