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Assume that I have the following line:

group blue:green yellow green redtomblue black !greyTOMwhilte !purple redblue

I need to delete from it all words that contain the string "tom" or "TOM" using sed.

I have managed to get this far:

sed 's/^ *\(.*\)[!]*[A-Za-z0-9_]*[tT]\{1\}[oO]\{1\}[mM]\{1\}[A-Za-z0-9_]*\(.*\)/\1 \2/g'

But this only deletes the last occurrence, not all of them. Using my example above the result is:

group blue:green yellow green redtomblue black !grey  !purple redblue

How can I use sed to remove any word containing either of the specific substrings "tom" or "TOM"?

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1 Answer 1

What about this one?

sed 's/\S*\(tom\|TOM\)\S*//g'

resp. in non-GNU versions of sed this should work:

sed 's/[a-zA-Z0-9_!]*[Tt][Oo][Mm][a-zA-Z0-9_!]*//g'

This will substitute all words (i.e. strings beginning with 0 or more non-whitespace characters (\S) followed by tom or TOM and again 0 or more non-whitespace characters) with an empty string.
Probably you should also remove double spaces:

sed 's/\S*\(tom\|TOM\)\S*//g;s/\(\s\)\s*/\1/g'
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@Sims: I added another version which should work with non-GNU sed versions. –  bmk Jul 18 '11 at 9:51
    
Worked, thanks a lot!!!! –  Sims Jul 18 '11 at 14:28

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