Unix find command help

Question

Hi can anybody help me with the following line;

find . \( -type d ! -name . -prune \) -o -type f -name "*Log*"

Basically it should find directories where files with "Log" in their name are present.

I have a structure like this:

/logs
  |
  |
  ----folder1
  |       |
  |       |
  |       ---App1LogDate.txt
  |
  ----folder2
  |      |
  |      |
  |      ---App2LogDate.txt
  |
  |
  |--App3LogDate.txt
  |
  |--App4LogDate.txt

So given that I will run this line within /logs directory I should get the following results:

.
./folder1
./folder2

3 directories in total.

Answer 1

Slightly left-field, but based on the above description, the following should do exactly what you want:

find . -type f -name "*Log*" -print | sed -E 's/\/[^\/]+$//' | sort | uniq

Answer 2

find . -name *.Log -print 

This will give full path of all the files whose name ends with Log .

Answer 3

find . ( -type d ! -name . -prune ) -o -type d -name "Log"

tmp$ ls
App3LogDate.txt  App4LogDate.txt  folder1  folder2
tmp$ ls folder*
folder1:
App1LogDate.txt

folder2:
App2LogDate.txt
tmp$ find . \( -type d ! -name . -prune \) -o -type d -name "*Log*"
./folder2
./folder1
tmp$

Answer 4

If you have GNU find (as Linux and many other modern Unixes do), you can just use the awesome printf operator and do this:

find -type f -name '*Log*' -printf '%h\n'

You probably also want to pipe that through a sort -u (or through sort | uniq, as appropriate). Note that some commercial UNIX implementations will have that installed as gfind (or have a package that installs it as such).