Super User is a question and answer site for computer enthusiasts and power users. It's 100% free, no registration required.

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

I just got a USB mouse that is 1600 dpi, while my normal one is 800 dpi. As a result, when I move the new mouse, the cursor flies around the screen at double speed.

If I reduce the speed in the mouse control panel applet, then the new mouse works smoothly, but then the old one is slow and sluggish.

It seems that Windows is using the same speed settings for all pointer devices connected to the system, which of course is no good for this exact sort of reason.

Hoping that the mouse control-panel applet is merely an interface to the registry, I checked HKEY_CURRENT_USER\Control Panel\Mouse, but it has only a single set of values for the speed and acceleration curve. I also checked the CurrentControlSet and found the settings that can be set for each pointer device via the Device Manager such as wheel-detection and packet-size, but nothing related to speed.

Is there a way to set the speed/acceleration for each pointer device individually?

share|improve this question
What OS is this? – digitxp Aug 25 '11 at 4:00
Windows (hence control panel). – Synetech Aug 25 '11 at 4:50
Did you know that the movement / distance travelled relationship of a mouse is measured in mickeys - I kid you not! – Linker3000 Aug 25 '11 at 8:16
@Linker3000, as a matter of fact I did know that. I just pulled out my copy of Microsoft Mouse Programmer’s Reference (2nd edition): “The motion of the mouse track ball translates into values that express the direction and duration of the motion. These values are given in a unit of distance called a mickey, which is approximately 1/200 inch (1/400 inch for a 400 ppi mouse). …” – Synetech Aug 26 '11 at 0:32

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Browse other questions tagged or ask your own question.