Notepad++ flip line order?

Question

I want to flip line orders of a document with 500+ lines... Not only numbers... it's a mix.

Example:

=

If it's not available in Notepad++ then other software whould be good also :)

Answer 1

Well, since we are giving code examples, If you are on Windows 7 or you have installed Powershell on another version of windows, then:

$foo = New-Object System.collections.arraylist;
$foo.AddRange($(Get-Content 'C:\Path\To\File.txt));
$foo.Reverse();
$foo | Out-File C:\Path\To\File.txt

Or for a non-coding answer, download GVim, open the file and type:

:g/^/m0

Answer 2

Solution not requiring other software except normally-included TextFX plugin:

1. Edit > Select All
2. TextFX > TextFX Tools > Insert Line Numbers
3. If TextFX > TextFX Tools > +Sort ascending is checked, uncheck it
4. TextFX > TextFX Tools > Sort lines case sensitive (at column)
5. TextFX > TextFX Tools > Delete Line Numbers or First Word

Answer 3

If you're comfortable compiling C++, this should do the trick. Basically, I put each line of the file in a vector, and output it to a new file by using a reverse iterator.

#include <iostream>
#include <fstream>
#include <string>
#include <vector>

int main()
{
    std::vector<std::string> fileLines;
    std::string              currLine;
    std::ifstream            inFile("input.txt");
    if (inFile.is_open())
    {
        while (inFile.good())
        {
            std::getline(inFile, currLine);
            fileLines.push_back(currLine);
        }
        inFile.close();
    }
    else
    {
        std::cout << "Error - could not open input file!\n";
        return 1;
    }

    std::ofstream outFile("output.txt");
    if (outFile.is_open())
    {
        std::vector<std::string>::reverse_iterator rIt;
        for (rIt = fileLines.rbegin(); rIt < fileLines.rend(); rIt++)
        {
            outFile << *rIt;
        }
        outFile.close();
    }
    else
    {
        std::cout << "Error - could not open output file!\n";
        return 1;
    }
    return 0;
}

If the output file is missing line breaks between the lines, then change the outFile << *rIt; to be outFile << *rIt << "\r\n"; so a line break is added (omit the \r if you're on Unix/Linux).

Disclaimer: I have not tested this code (I wrote it real quick in Notepad), but it looks viable.

Answer 4

Here is a non-coding way:

1. Download/Install TextPad free trial
2. Open a spreadsheet program (ie Excel) and create numbers 1000 through 1500 in column "A" by putting a "1000" in cell A1, then putting A1+1 in cell A2, then copy that down to A500.
3. Open your text file in TextPad
4. Change to "block mode" in TextPad
5. Paste column A from the spreadsheet into TextPad (all will end up on the left margin due to block mode)
6. Use TextPad sort feature, descending
7. Use TextPad block mode delete to get rid of the numbers

Answer 5

here is a C# .NET code for it i just wrote :)

class Program
{
    static void Main(string[] args)
    {
        try
        {
            String line;
            Stack<String> lines = new Stack<string>();
            // Create an instance of StreamReader to read from a file.
            // The using statement also closes the StreamReader.
            using (StreamReader sr = new StreamReader("test.txt"))
            {
                // Read and display lines from the file until the end of
                // the file is reached.
                while ((line = sr.ReadLine()) != null)
                    lines.Push(line);
            }
            // create a writer and open the file
            TextWriter tw = new StreamWriter("test2.txt");
            // write a line of text to the file
            while (lines.Count > 0)
                tw.WriteLine(lines.Pop());
            // close the stream
            tw.Close();
        }
        catch (Exception e)
        {
            // Let the user know what went wrong.
            Console.WriteLine("The file could not be read/written:");
            Console.WriteLine(e.Message);
        }
    }
}