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If I've understood this correctly, the Round-Robin scheduler maintains a list of processes, where each process has one entry. But what happens if the same process appears twice?

Does it crash or reports an error, or just gives it more CPU time?

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closed as not a real question by sblair, grawity, slhck, Mokubai, Sathya Sep 27 '11 at 2:51

It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.If this question can be reworded to fit the rules in the help center, please edit the question.

I would guess that, since the scheduler itself maintains the list, such a condition would only be caused by a bug. How the bug is dealt with very much depends on the particular operating system type and even version. Linux? Linux 2.4? Linux 2.6? Linux Windows? Windows NT 6.1 SP2? Plan9, yesterday's build? – grawity Sep 26 '11 at 7:10
No specific OS or platform. General question. – Jan Helge Sep 26 '11 at 12:07
"It could be both, or neither, or it could make your computer explode while curing cancer in the background." General answer. – grawity Sep 26 '11 at 12:14