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I have three PCs

  • 192.168.1.100 (DHCP)
  • 192.168.1.101 (DHCP)
  • 192.168.1.113 (Static)

One router (SMC SMC8014WN)

  • 192.168.1.1

The .100 and .101 both have access to the internet. The .113 does not.

I check to make sure that .113 is within the DHCP range (.100-.150) of the router. I also set a previously working computer .101 to .107 and it could not connect to the internet.

The router is provided by my ISP (SHAW internet) and I do not have the ability to replace it.

My question is:

  • What would cause a computer with a static IP address not to have access to the WAN while a DHCP'ed computer would.

Update 1

What I mean by "Can not access to the WAN" is that I can not ping an external IP address for example .113 can ping .100 and .101 but can not ping 173.194.33.52 (google.com)

I am not using DNS, but just to check I set the DNS to 8.8.8.8 and I am still having the same issue.

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Are you setting the default gateway to the router address? –  chunkyb2002 Nov 3 '11 at 21:11
    
@chunkyb2002: Yes I am sure the all three computers have the default gateway set to 192.168.1.1 –  Steven smethurst Nov 3 '11 at 21:18
    
Did you set the DNS server on the static PC? When you say you can't access the internet, what have you tried? Can you ping an IP address on the internet? Can you perform hostname lookups (using host, nslookup, or dig)? –  Klox Nov 3 '11 at 21:28
    
Have you tried pinging any URL? Have you set DNS servers? It should also be set to the router address (unless you have your own dedicated DNS Server) or some external DNS server like Google's 8.8.8.8 and 8.8.4.4 –  chunkyb2002 Nov 3 '11 at 21:31
2  
Try setting the static IP address OUTSIDE of the DHCP range, but in the same subnet? –  Canadian Luke Nov 3 '11 at 21:40
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2 Answers

up vote 2 down vote accepted

Set the static IP address OUTSIDE of the DHCP Range, but still in the same subnet

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You cannot set a static IP address to one within the DCHP range, if that particular address has already been reserved.

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Waiting on 'luke' to post a answer this question as he was the first to answer it as a comment, But you are correct as well. –  Steven smethurst Nov 3 '11 at 22:20
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