# How do I symmetrically encrypt a file using gpg?

I'm trying to symmetrically encrypt a file using gpg.

$gpg --encrypt --symmetric$MYFILE


I enter and re-enter a passphrase, then gpg tells me

You did not specify a user ID. (you may use "-r")

Current recipients:

Enter the user ID.  End with an empty line:


I don't know what to enter here. I'm symmetrically encrypting (not public key encrypting) so I don't understand why gpg wants to know who the recipient might be. I don't know what the sort of user id gpg is expecting looks like, and I don't know any gpg user ids anyway. If I just enter an empty line, gpg complains that there are "no valid addressees".

So how do I symmetrically encrypt a file using gpg?

Version: gpg (GnuPG) 1.4.11, as packaged in Ubuntu 11.10.

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The correct command is gpg --symmetric \$MYFILE.
The encrypt option tells it to use public-key encryption. The "id" it is asking for is the id of the public key, which you must have in your keyring. (Usually you use an email address for this, but there are other ways to specify which public key to use.)
I just wanted to clarify, but my version of Gnupg, when I pass both --symmetric and --encrypt --recipient foo makes for an encrypted message that requires either the private key of the recpipent or the passphrase. In effect, the passphrase allows decrypting the message without any private key. You should update your answer, so people don't start making bad decisions :-) –  mogsie Mar 8 '13 at 9:18