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I'm converting Windows batch script .bat to Linux batch script .sh

What takes time a lot is to change the way .bat script use variables.

i.e.

In Windows

@set varName=122
echo %varName%

In Linux

varName=122
echo $varName

So the question is, how to replace %.+% to $.+ ?

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You should accept your own answer if you don't expect there to be another better solution. –  JustinStolle Dec 4 '11 at 21:09

1 Answer 1

up vote 5 down vote accepted

In the Replace dialog (Ctrl+H), use the following:

Find what: %(.+)%
Replace with: $\1
Search Mode: Regular expression

screen shot of replace dialog

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