Suppose I create a directory
test/, with two files (
test/b) and an inner directory
test/c with a file
test/c/d, like this:
mkdir test cd test touch a echo 1 > a touch b echo 1 > b mkdir c cd c touch d echo 1 > d cd ../.. du test -ab
The output of the last line (running
2 test/a 4096 test/c 2 test/b 8196 test
The size of the directory is 8196 (instead of 6, which would be: size of file a + size of file b + size of file c/d). This is because, as i understand it, du includes the size of directories themselves (because a directory is just a special file, which records file entries in it).
I don't want that. I want to see the combined size of all the files in a directory (the way Windows Explorer reports directory size). So in this example, the result should be:
2 test/a 2 test/c 2 test/b 6 test
More importantly, what I really want is that last line: the sum of sizes of all the files in the directory (recursively).
But I have gone through all the options of du, and there doesn't seem to be a way to do this. Is there any way?