jdk not being picked up by vista, but the path is correct

Question

Here is my path :

C:\Program Files\ICW>path
PATH=C:\Windows\system32;C:\Windows;C:\Windows\System32\Wbem;c:\Program Files\Mi
crosoft SQL Server\90\Tools\binn\C:\Program Files\TortoiseSVN\bin;F:\downloads\a
gntctrl.win_ia32-TPTP-4.7.1a\bin; C:\Program Files\Java\jdk1.7.0_02\bin;

and javac is not recognized :

C:\Program Files\ICW>javac
'javac' is not recognized as an internal or external command,
operable program or batch file.

So I cd to directory to prove it works:

C:\Program Files\ICW>cd "C:\Program Files\Java\jdk1.7.0_02\bin"

and it works

C:\Program Files\Java\jdk1.7.0_02\bin>javac
Usage: javac <options> <source files>
where possible options include:
  -g                         Generate all debugging info

BUT the Java app(?) in control panel (which I have never seen/used before) shows the jre is installed, and everytime I try and reference the jdk it just overwrites it, see below. I am embarrased to admit I have over 10 years experience as a java developer ... which btw is unaffected, eclipse/maven are picking up jdk correctly. Its just the windows command prompt.

Answer 1

You need to remove the space before C:\Program Files\Java\jdk1.7.0_02\bin; in your PATH as well as add a ; after this entry c:\Program Files\Microsoft SQL Server\90\Tools\binn\

I'm also guessing that binn is a typo?