How to write a script that does what less does?

Question

Question: Create a script such that it is a command that has the same effect as the "less" command (implement the script by calling "less").

What I wrote:

#! /bin/bash
for index in "$@"
do
  less "$index"
done

Apparently this is wrong. Any suggestions?

Answer 1

Why not this..

#!/bin/bash
less "$@"

Although i guess what your teacher meant was to make a script which works like less without using less.