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What command can I use to get IPv6 address of an interface in a script?

Update: Output of sed from one of answers.

$ ip -6 addr
1: lo: <LOOPBACK,UP,LOWER_UP> mtu 16436 
    inet6 ::1/128 scope host 
       valid_lft forever preferred_lft forever
3: wlan0: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qlen 1000
    inet6 fe80::224:d7ff:fed0:4f5c/64 scope link 
       valid_lft forever preferred_lft forever

The other:

$ ip addr show dev eth0 | sed -e's/^.*inet6 \([^ ]*\)\/.*$/\1/;t;d'
$ ip addr show dev eth0
  2: eth0: <NO-CARRIER,BROADCAST,MULTICAST,UP> mtu 1500 qdisc pfifo_fast state DOWN qlen 1000
  link/ether f0:de:f1:7b:e9:6c brd ff:ff:ff:ff:ff:ff
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Which IPv6 addresses? Your interfaces' IPv6 addresses? – m0skit0 Feb 14 '12 at 13:27
    
Yes, edited, thx. – Ondra Žižka Feb 21 '12 at 4:33
up vote 7 down vote accepted

You could use:

ip -6 addr

It will return all the IPv6 adresses you have configured.

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There are lots of ways you could do this.

Here is one:

ip addr show dev eth0 | sed -e's/^.*inet6 \([^ ]*\)\/.*$/\1/;t;d'

It is similar to Robert's answer, except strips out the address only.

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