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Say I have some file with a bunch of lines in the form

someString=someMoreCharacters
anotherString.blah=foo=bar
blah.blah.blah=foo.bar.=foobar

Desired output

someString
anotherString.blah
blah.blah.blah

I want to use awk to extract the substring that starts at the beginning of the line and goes up until, but not including the first equals sign. I want to be able to pipe this output to xargs.

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sed's greediness makes this a quick fix, sed 's/=.*//', although I've never done anything with awk. –  Rob Mar 16 '12 at 18:06

1 Answer 1

up vote 4 down vote accepted

In Awk:

awk '{sub(/=.*/, ""); print}' filename

But, I think Rob's solution is easier:

sed 's/=.*//' filename
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