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I often pipe program output to less, e.g.

produce_output | less

This works great, until produce_output produces large amounts of output. If I search for some text that is deep into the file, less reports

Calculating line numbers... (interrupt to abort)

If I interrupt with Control+C, it also kills produce_output, which stops it from producing further output. Is there any way to send the interrupt to less, so that produce_output keeps running?

I know that I could use kill -INT less_process, but I think there must be a better solution.

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3 Answers 3

up vote 4 down vote accepted

Normally all processes in a pipeline run in the same process group, causing all of them to receive the signal. You can use setsid foo | less to run foo in a different pgrp.

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Thanks, exactly what I was looking for! –  Ed McMan May 10 '12 at 0:50

You can disable line numbers with the

   -n or --line-numbers


produce_output | less -n
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-1: may solve OP's instigating problem, but does nothing to answer OP's actual question (i.e., interrupting a process). –  goldPseudo May 10 '12 at 0:15
Sorry but starting less with a feature that is not wanted and then try to send a signal to disable a feature you can disable with a switch is a workaround and not a solution. Of course @grawity solution is nice (and I up voted it) but come on: starting the first process in another group to be able to send a signal to interrupt a task (line counting) that is not needed is really a little bit too much work. –  Matteo May 10 '12 at 5:26
This is a fair solution to the problem I posed in my question. However, interrupts stop more than just the line counting in less -- for instance, they will interrupt a long search too. So, @grawity's solution is preferred, since it would cover any use of interrupts in less. My bad for not addressing this more clearly in the question! –  Ed McMan May 10 '12 at 13:38
@EdMcMan Sure I also up voted gravity's solution and I happy to learn something new that can always be useful. –  Matteo May 10 '12 at 13:59

In working with large amounts of output, I've found it very helpful to send the output to a file and use tail -f or less +F to watch, e.g.:

produce_output > out 2>&1 & less +F out

The 2>&1 syntax makes sure that both stdout and stderr go to out---remove that if you only want stdout going to the file. This way, you can inspect the output in various ways (even from a different machine) without having to mess with the program producing the output.

Note that 2>&1 may be bash-specific (I'm not sure). Be sure that you have sufficient disk space for the output file :-)

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Tail will just show you the file, Ed specified that he is using less interactively (e.g., he has to search in the file) –  Matteo May 9 '12 at 15:03
2>&1 is POSIX, bare >& is a bashism. –  grawity May 9 '12 at 15:17
FWIW, 2>&1 also works on Windows XP, 7, 2008, etc. –  jftuga May 9 '12 at 16:05
@Matteo: yes, I should have used less +F in my example; I just updated my answer. –  jrennie May 9 '12 at 22:10
@Matteo: Line counting is not the same issue with less +F (since less +F processes the data as it is generated). The example I gave does not have the same problem as originally posted: ctrl+c will not interrupt process_output. If one doesn't care for the 'follow' functionality, one can run produce_output > out 2>&1, then less out. A problem with produce_output | less is that if anything breaks the pipe (e.g. accidentally hitting 'q' from less), then produce_output will die (without special SIGPIPE handling). –  jrennie May 10 '12 at 2:15

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