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currently i am rename my file with below command line i want to add alphabetic character to each file name like file-a.jpg file-b.jpg

dir im* | ForEach-Object -begin { $count= 1 } -Process { Rename-Item $_ -newname
"img$count.jpg"; $count++} 
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What would happen if there's more than 26 files? – Ƭᴇcʜιᴇ007 Jun 1 '12 at 6:16
    
I think i can use below command but if you have any better solution then show me @techie007 dir *.jpg | foreach-object -begin { $count= 1 } -process { rename-item $_ -Newname " image-$([char](64 + $count))$([char](96 + $count)).jpg"; $count++}' – raj Jun 3 '12 at 12:17
up vote 3 down vote accepted

You can use the [char] class to convert an integer to an ASCII character.

ASCII code 97 is character a, so you could use 96 + the current loop count ($count); something like:

dir im* | ForEach-Object -begin { $count= 1 } -Process { Rename-Item $_ -newname
"file-$([char](96 + $count)).jpg"; $count++}

I haven't tested your/this code exactly, so you may have to fiddle with it a bit. :)

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Shouldn't it be "file-$([char](96 + $count)).jpg"? – Bob Jun 1 '12 at 6:29
    
Probably. ;) Let me fix that.. – Ƭᴇcʜιᴇ007 Jun 1 '12 at 6:31
2  
@raj $() means evaluate the contents and substitute them. It can be used within strings quoted with " quotes. [char] casts the value following it as an ASCII code into a character. The value following it is (96 + $count). ASCII code 97 is a, so when the variable $count is equal to 1, you get 97 which is cast into a. $count++ increments the $count variable (++ increases the value of a variable by one). – Bob Jun 1 '12 at 11:38
1  
Thanks for helping me and giving your valuable time @Bob techie007 – raj Jun 1 '12 at 17:36
1  
@raj I should warn you that special characters, possibly invalid in filenames, will start to appear after z, when $count exceeds 26. You never did reply to techie007's comment on the question asking what to do in that case. – Bob Jun 1 '12 at 17:42

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