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How to extract a complete list of extension types within a directory?

Suppose there are three files, a.txt b.txt c.exe under folder c:\dir\, is there any command that I could get the two file extensions names .txt and .exe.

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    Just remove the /s in dir /b /s /a:-d "%target%" in my answer to exclude subdirectories.
    – Bob
    Jun 16, 2012 at 3:09
  • A solution for powershell is here: superuser.com/a/397961/26503
    – Steve Rathbone
    Jun 16, 2012 at 6:12
  • This should work: dir /a-d /b | sed -e "s/^.*([.][^.]*)/\1/g" | sort | uniq
    – Kevin Fegan
    Nov 15, 2012 at 1:45

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I'm not sure what you're asking. I think you want to know a DOS command to list all files with a filename extension ending in both .txt and .exe? For that I'd just type in "DIR C:\DIR\*.EXE; C:\DIR\*.TXT" (Notice the space after "DIR" and a space after the semicolon. Also don't include the quotes.)

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  • No. The body of the question is confusing, but the title is more clear. They wanted to query a directory and get a list of unique file extensions based on the files present.
    – iglvzx
    Jun 16, 2012 at 6:34

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