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How to extract a complete list of extension types within a directory?

Suppose there are three files, a.txt b.txt c.exe under folder c:\dir\, is there any command that I could get the two file extensions names .txt and .exe.

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marked as duplicate by Bob, iglvzx, sudo, slhck, Mokubai Jun 16 '12 at 6:31

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Just remove the /s in dir /b /s /a:-d "%target%" in my answer to exclude subdirectories. –  Bob Jun 16 '12 at 3:09
    
A solution for powershell is here: superuser.com/a/397961/26503 –  Steve Rathbone Jun 16 '12 at 6:12
    
This should work: dir /a-d /b | sed -e "s/^.*([.][^.]*)/\1/g" | sort | uniq –  Kevin Fegan Nov 15 '12 at 1:45

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I'm not sure what you're asking. I think you want to know a DOS command to list all files with a filename extension ending in both .txt and .exe? For that I'd just type in "DIR C:\DIR\*.EXE; C:\DIR\*.TXT" (Notice the space after "DIR" and a space after the semicolon. Also don't include the quotes.)

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No. The body of the question is confusing, but the title is more clear. They wanted to query a directory and get a list of unique file extensions based on the files present. –  iglvzx Jun 16 '12 at 6:34

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