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I want to write a script, but I want an if statement so it will run only if the number of files in the directory are greater than 1. Is this possible?

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What have you tried? Paste your current script in the question to solicit better answers! – Ozair Kafray Jul 2 '12 at 12:17
The script is too large to fit in this box. I haven't tried anything yet since I don't have a clue how to do this. – jlacroix82 Jul 2 '12 at 12:56
@jlacroix82: You can paste the script in pastebin and put the link here. – criziot Jul 2 '12 at 13:08
Here it is in Pastebin: Please note that I am very sensitive about the script, I don't want anything changed other than the added functionality I'm requesting. I put comments where I want it to check if there are more than one file before doing it. – jlacroix82 Jul 2 '12 at 16:01

Something like

[ "$(ls -b | wc -l)" -gt 1 ] && { ... your statements ... }
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Is there any way to do it with an if statement? – jlacroix82 Jul 2 '12 at 12:24
That is a (hidden/abbreviated) if..then statement. In full length, it would read if [ "$(ls -b | wc -l)" -gt 1 ]; then ... your statements ...; fi – Izzy Jul 2 '12 at 12:30
The statements still run whether there is more than 1 file in the directory or not. Should I increase -gt 1 to -gt 2? – jlacroix82 Jul 2 '12 at 12:54
@jlacroix82: Don't forget this will also count directories, not only files. So if you have two directories inside the current directory the test will succeed even if there are no files. – criziot Jul 2 '12 at 14:33
There are no subdirectories at all, unless it's counting .. – jlacroix82 Jul 2 '12 at 15:54

I needed to use this:

shopt -s nullglob
files=($dir/*) # $dir was declared earlier if you look at my script
if (( "${#files[@]}" >= 2 ));
shopt -u nullglob

The reason why none of the solutions posted here worked is because of the following. The script is executing the statements AGAINST the directories, it's not actually CD'ing IN to the directories. By telling it what folder I'm working with ($dir) it gets the hint and works as expected.

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So the problem is basically what I've told you in my comment. Anyway I've edited my answer so you can see how to use a specific directory, but I'm glad you found a solution. – criziot Jul 2 '12 at 20:13

I will use something like:

    nf=`find . -maxdepth 1 -type f | wc -l`

    if [ "$nf" -gt "1" ] ; then
            <do something here>

This approach will only count files in the directory pointed by dir and discard any possible subdirectory.

Don't forget to change dir accordingly to your needs.

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Just tried it, and the <do something here> will not run, even if there are files in the directory. – jlacroix82 Jul 2 '12 at 12:38
The [ test ] statement may be incorrect: it uses strings (in quotes), but a numeric comparision (-gt). Try replacing that part by [ $nf -gt 1 ] (for a numeric comparision). If you want to do that with strings, it should be [ "$nf" != "0" -a "$nf" != "1" ]. Moreover you could (for test purposes) output the value stored in $nf before the line starting with "if". – Izzy Jul 2 '12 at 12:49
@Izzy: That's wrong. The comparisson works with Strings. – criziot Jul 2 '12 at 12:57
@jlacroix82: Please. Make sure the current directory is what you want. Don't forget the find is finding files in the current directory. If you want you can change find . to find <directory>. Also you can put the command pwd in your script to know what is your current directory. The script was tested and it works. – criziot Jul 2 '12 at 12:59
@criziot: it may work (as sorted alphanumerically, any "string-number" larger than 1 starts with the digit 1 or up), but a) not good style and b) you never know about implementations whether "string -gt string" gets silently converted. The man page of test explicitly states: INTEGER1 -gt INTEGER2: INTEGER1 is greater than INTEGER2. Nothing about strings with "-gt". But don't we argue -- as long as it works ;) – Izzy Jul 2 '12 at 13:22

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