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The command executed in the following script works:

#!/bin/bash -xv
SSHOPTS="-C -c arcfour256 -o "\""ServerAliveInterval 15"\"

CMD="ssh $SSHOPTS \"$SSHUSER\" \"find \\\"$REM_DIR/\\\" -path *lost+found -prune -o -type f -printf \\\"%P\\\\n\\\"\""

It basicaly executes this on the remote host:

find "/home/jan/rem-dir/" -path *lost+found -prune -o -type f -printf "%P\n"

But how should it be escaped/formatted if I want it this way:

REM_FILES=`ssh ...`


REM_FILES=$(ssh ...)

Though my current script run just fine, I would like to know how to properly escape/quote when shell scripting.

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I think youll get more support for this type of question here – Rhyuk Jul 13 '12 at 14:46
That sort of question is entirely on topic on SU as well – Journeyman Geek Jul 13 '12 at 15:19
Please see BashFAQ/050 in other words, don't use all those variables. – Dennis Williamson Jul 14 '12 at 0:50

A better way is:

#!/bin/bash -xv
SSHOPTS=(-C -c arcfour256 -o "ServerAliveInterval 15")

REM_FILES=`ssh "${SSHOPTS[@]}" "$SSHUSER" "find \"$REM_DIR/\" -path \"*lost+found\" -prune -o -type f -printf \"%P\\n\""`

The main problem was with $SSHOPTS, the trick is to put each argument in a separate element of an array.

@Dennis thanks for the useful link.

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