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My situation has 2 directories: /blah/d01 and /blah/d02

$ls -l /blah/d01
a/
b/
c/
fa -> a
fb -> b
fc -> c

and I want to copy fa, fb, fc to /blah/d02, and as a result:

$ls -l /blah/d02
fa -> ../d01/a
fb -> ../d01/b
fc -> ../d01/c

the point is, I want to do something like cp --{some magic attr} /blah/d01/f* /blah/d02/ to make this happen.

Thanks

UPDATE

I settled with a bash script:

#! /bin/bash
for i in $@; do echo $i && [ -L $i ] && ln -s $(dirname $i)/$(readlink $i) $(basename $i); done

which make newlinks based on old ones(make sure that they use relative path)

UPDATE AGAIN

I found my last script works but the link path would be awkwardly long(full with strange relative paths) after copy symlinks from a to b and from b to c, so I added something to cleanup relative path, and the script ends:

#! /bin/bash
function relpath {
  source=$1
  target=$2

  common_part=$source
  back=
  while [ "${target#$common_part}" = "${target}" ]; do
    common_part=$(dirname $common_part)
    back="../${back}"
  done

  echo ${back}${target#$common_part/}
}

for i in $@; do echo $i && [ -L $i ] && ln -s $(relpath $PWD $(readlink -f $i)); done
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2 Answers

up vote 1 down vote accepted

As those symlinks are created w/o full qualified path, that's a thing hard to do with cp. But you could rather create new ones at the target:

for i in *; do [ -L $i ] && cd blah && ln -s ../$i $i && cd -; done

Short explanation:

  • for i in *: Loop over the list of files/directories in the currend location
  • do: encapsulate what has to be done
  • [ -L $i ] &&: only continue if the current entry is a symbolic link
  • cd blah && ln -s ../$i $i && cd -: change to blah and create symlinks to the original location

That's not yet exactly what you want (as it symlinks the symlinks). So we will modify it a bit:

for i in *; do [ -L $i ] && cd blah && ln -s ../$(readlink ../$i) $i && cd -; done

The added construct $(readlink ../$i) evaluates the object the link points to, and places the result there instead. Et voila -- the result is what you were looking for.

Note that I simplified your request a little (making it as if you'd just want to copy the symlinks to a subdirectory), so it is easier to follow. You have to adjust it either, as I do not assume your real directory is called blah :)

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@lzzy that's really decent of you, thanks! maybe I should save this script :D –  tdihp Jul 24 '12 at 9:25
    
@tdihp good idea. And don't forget to accept (or at least up-vote) the answer if you like it :) –  Izzy Jul 24 '12 at 9:50
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I think you should use full path instead relative path as

fx -> /full/path/to/x

So when you copy link it will always show x.

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Doing this your way is acceptable, despite the trouble to provide abs path when ln ... thanks –  tdihp Jul 24 '12 at 9:45
    
And sadly, I just find out that I want it relative, to work under nfs, too... –  tdihp Jul 24 '12 at 10:04
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