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sha1sum ./path/to/directory/* | sha1sum 

the above was posted as a way to compute a sha1sum of a directory which contains files. This command fails if the directory includes more directories. Is there a way to recursively compute the sha1sum of a directory of directories universally (without custom fitting an algorithm to the particular directory in question)?

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3 Answers 3

up vote 3 down vote accepted

Thanks to this SO post

find . -type f \( -exec sha1sum "$PWD"/{} \; \) | sha1sum

Warning: This code is untested! Edit this question if it's wrong and you can fix it; I'll approve your edit.

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Sorry; I couldn't resist! ;-) Recursion is fun. Of course there's a way. I'll write up a proper answer now. –  allquixotic Aug 6 '12 at 20:12

I generally like the "find | xargs" pattern, like so:

find ./path/to/directory/ -type f -print0  | xargs -0 sha1sum

You have to use the "-print0" and "-0", in case there are spaces in file names.

However, this is very similar to the "find -exec cmd {}" pattern.

See a discussion comparing the two patterns here: http://stackoverflow.com/questions/896808/find-exec-cmd-vs-xargs

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This seems to work for me:

find . \( -not -name . \) -type f -exec cat {} + | sha1sum

EDIT: this will only sha1sum all of the files contained in the directory tree. If a directory's name was changed, this wouldn't catch it. Maybe something like:

find . -exec sha1sum {} + 2>&1 | sha1sum

Would do it. About the same answer as the other one though

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