Take the 2-minute tour ×
Super User is a question and answer site for computer enthusiasts and power users. It's 100% free, no registration required.

Well, i am subscribed to local ISP for 8 Mbps downstream for two computers at home managed by WAG120N broadband modem. it may not be enough when simultaneously watching a video at both computers. On the other hand, i imagine what internet connection speed is adequate for a cyber cafe consisting of 30-40 client computers considering this fact ?

Edit : lets say, we don't want any interruption/drops and many PC's are used to play online games, watching videos at the same time.

share|improve this question

closed as not constructive by RedGrittyBrick, Diogo, Xavierjazz, Breakthrough, Renan Aug 11 '12 at 2:34

As it currently stands, this question is not a good fit for our Q&A format. We expect answers to be supported by facts, references, or expertise, but this question will likely solicit debate, arguments, polling, or extended discussion. If you feel that this question can be improved and possibly reopened, visit the help center for guidance.If this question can be reworded to fit the rules in the help center, please edit the question.

1 Answer 1

I would say 1-2 Mbps per PC should be more than enough.
This will suffice for HD video streaming as well as playing MMORPGs.

But assuming not all the PCs would be doing heavy usage at the same time, cosider allotting 512 Kbps to each PC.
But again that will depend on kind of customers you expect. If all the PCs are to be used for online gaming at same time, then 512Kbps per PC would not suffice.

In case of reliability, that will depend on service providers which will specific to your country.

share|improve this answer
    
what does 1-2 Mbps per client exactly mean? for 30-40 client , i should have 1-2 multiply 30-40 client ? –  Ozgun S Aug 11 '12 at 9:19
    
MMORPGs rather need low latency not high bandwidth –  AnonymousLurker Aug 11 '12 at 9:27

Not the answer you're looking for? Browse other questions tagged or ask your own question.