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Suppose I have a bash shell script called that need on argument as input.

But I want the content of the text file called text.txt to be that argument.

I have tried this but it does not work:

# cat text.txt | ./

Do we have a way to do it?

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up vote 7 down vote accepted

Command substitution.

./ "$(cat text.txt)"
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You can use pipe output as a shell script argument.

Try this method:

cat text.txt | xargs -I {} ./ {}
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If you have more than one command in the file, consider using xargs or parallel, e.g.

xargs -d '\n' < text.txt
parallel -j4 < text.txt
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 # cat comli.txt

 # cat
 which $1

 # for i in `cat comli.txt` ; do ./ $i ; done

so you can enter the values one by one to from comli.txt.

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