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I would like a BASH command to list just the count of files in each subdirectory of a directory.

E.g. in directory /tmp there are dir1, dir2, ... I'd like to see :

`dir1` : x files 
`dir2` : x files ...
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2 Answers

up vote 2 down vote accepted

Assuming you want a recursive count of files only, not directories and other types, something like this should work:

find . -maxdepth 1 -mindepth 1 -type d | while read dir; do
  printf "%-25.25s : " "$dir"
  find "$dir" -type f | wc -l
done
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works perfectly! thanks. –  jldupont Sep 14 '12 at 21:36
    
Also, I get "find: warning: you have specified the -maxdepth option after a non-option argument -type, but options are not positional (-maxdepth affects tests specified before it as well as those specified after it). Please specify options before other arguments." –  jldupont Sep 14 '12 at 21:38
1  
Both answers given so far will give incorrect results in the unlikely case that there are files whose names include newline characters. You can handle that with a find ... -print0 | xargs -0 .... –  Scott Sep 14 '12 at 21:57
    
@jldupont: move the depth arguments before the ´-type d´, I've edited the answer. –  Thor Sep 14 '12 at 22:58
    
bonus points for nice formatting! –  Andreas Petersson Nov 1 '13 at 7:09
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Using find is definitely the way to go if you want to count recursively, but if you just want a count of the files directly under a certain directory:

ls dir1 | wc -l

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I don't want to do this for each of the 1000's of directories I've got there... –  jldupont Sep 14 '12 at 21:37
    
Then use xargs. ls -d */ | xargs -n1 ls | wc -l (Use the answer you accepted if it already works, though! This is just And Now You Know.) –  jrajav Sep 14 '12 at 21:41
    
your proposal didn't show up any results in many seconds whereas the answer I accepted did. –  jldupont Sep 15 '12 at 8:03
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