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Using sed, how would I change Popeye’s birthday to 11/14/46? Assume you don’t know Popeye’s original birthday.

The input filename is datebook, as follows:

Arthur Putie:923-835-8745:23 Wimp Lane, Kensington, DL 38758:8/31/69:126000
Popeye Sailor:156-454-3322:945 Bluto Street, Anywhere, USA 29358:3/19/35:22350
Jose Santiago:385-898-8357:38 Fife Way, Abilene, TX 39673:1/5/58:95600

I tried

sed ‘^\(/Popeye/s/[0-9]{5}\):/\1:11/14/46’ datebook 

but it did not work.

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What is your question? You want to write a parser to pick out the relevant data and replace it for you? That might be better on Stack Overflow, but as it is I'm not even sure this is a real question. –  Shinrai Oct 4 '12 at 19:58
    
Reopened since after the OP's clarification, this question became answerable. –  slhck Oct 4 '12 at 20:53
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1 Answer

up vote 2 down vote accepted

There are numbers, slash, numbers, slash, numbers. Use an alternate separator to avoid backslashed slashes:

sed '/Popeye/s,[0-9]\+/[0-9]\+/[0-9]\+,11/14/46,'
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Thank you Choroba. Appreciate your help. –  Steve Oct 4 '12 at 20:42
    
sed '/Popeye/s,[0-9]\+/[0-9]\+/[0-9]\+,11/14/46,' => This works great. Thank you Choroba –  Steve Oct 5 '12 at 7:36
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