I'm running CentOS 6 on a server that has two 80 GB internal drives, in a software RAID 1. I want to replace this two internal drives with 750 GB internal drives I have available.
How do I do this without rebuilding the system from scratch?
I am thinking of maybe booting up from DVD-ROM and just putting one of the larger drives in while leaving the old drive in there. Then, format the new drive and create partitions that match the smaller drive. Of course, the larger drive with different partition sizes cause there is more space to use) and rsync each partition over. Then repeat this process with putting in the second 750 GB drive and rsync it back from the other 750GB drive.
I'm concerned that I am overlooking something with this method.