Take the 2-minute tour ×
Super User is a question and answer site for computer enthusiasts and power users. It's 100% free, no registration required.

I am going to program some application that adds an exe file to Startup of user's windows.

I can easily do that, unless if Deep Freeze be installed on the windows, which doesn't allow me to do that.

Okay, I know that I might be able to beat Deep Freeze using a boot disk or something like that, but I want to do that by a program, which runs on windows.

I can't delete Deep Freeze or its DLLs, or change registry keys, because they are likely frozen, and they'll be back after restart.

Anyway?

share|improve this question
    
Down votes but no answer or comments? –  Mostafa Farzán Nov 4 '12 at 15:03
    
The answer is no there isn't any way other than a boot you control. –  Snesticle Nov 4 '12 at 15:07
    
@MostafaFarzán - How about disable Deep Freeze install your application the enable it again. As for the downvote, this is a localized problem, if you have permission to install the program then you have the ability to disable Deep Freeze. –  Ramhound Nov 4 '12 at 15:10
    
Okay, so I need someways to boot the computer and then I disable it. Thanks, here we go. –  Mostafa Farzán Nov 4 '12 at 15:29
    
If the user installs a program to prevent other programs from adding auto-start entries, then circumventing that program is against the user intend. So it sounds like you want to write malware. –  CodesInChaos Nov 4 '12 at 17:24

1 Answer 1

up vote 0 down vote accepted

Use an external medium to boot as that is the only way. You cannot do this programmatically. As per Wikipedia :

Deep Freeze cannot protect the operating system and hard drive upon which it is installed if the computer is booted from another medium (such as an external hard drive, a USB device, optical media, or network server).

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.