Shell command to remove a folder contents recursively excluding hidden files?

Question

I want to remove a folder contents and it's sub-folder contents without removing hidden files in folder and sub-folders. How can i do it by using shell script??

I have tried rm -rf foldername but it is removing entire contents.

Answer 1

Instead of using -exec or xargs, you can just do:

find folder_name -not -name ".*" -delete

• This removes all files and folders that do not start with . (hidden files/folders)
• This removes folders if and only if they are empty (so it won't remove folders containing hidden files, as required)

Answer 2

That's a tricky one. An outline solution might be:

find foldername -type f ! -name '.*' -exec rm -f {} +
find foldername -type d -depth -exec rmdir {} + 2>/dev/null

The first command removes files with a name not starting with .; the second tries to remove directories. The -depth option means remove sub-directories before removing directories. The + notation is from POSIX 2008 find but works fine on Mac OS X (10.7.5, anyway). The 2>/dev/null sends any 'directory not empty' error messages (and, indeed, all others) to oblivion.

You might run into issues with symlinks, Unix sockets, FIFOs, and other non-files; tweak the first command to suit your requirements. If you use ! for history, you might need to escape that.

Answer 3

by passing an argument -name "*" to the find command will leave by default all the hidden files.so you can use the below command.

  find . -name "*"|xargs rm -f

Answer 4

You could use this command:

find foldername/ -type f -not -name '.*' | xargs rm -f

The find command finds all files under foldername/ whose names don't start with a '.' (hidden file), and passes them to xargs, which runs rm -f on them.