Batch process ffmpeg?

Question

Given an AVI encapsulated video with WMA2 audio and MP4 video how do I pass-through the video, convert the audio to MP3; then re-encapsulate the entire file into an AVI?

ffmpeg -i "foo bar.avi" -acodec libmp3lame "Converted\foo bar.avi"

Now how do I do that same command for every .avi file in this directory?

(need a solution using bash or Windows CLI [for?])

Answer 1

Python solution

from sh import ffmpeg
from os import listdir
from os.path import split
from sys import argv

[ffmpeg("-i '{0}' -acodec libmp3lame 'Converted\{0}'".format(_file))
 for _file in sum([listdir(split(arg)[0]) for arg in argv], [])]

Answer 2

Do this not simply work?

for file in *.avi;do ffmpeg -i "$file" -acodec libmp3lame "Converted\\$file";done

Edit:

There seem to by a backslash problem...

Try this:

for file in *.avi;do ffmpeg -i "$file" -acodec libmp3lame 'Converted\\'"$file";done

or this:

for file in *.avi;do ffmpeg -i "$file" -acodec libmp3lame 'Converted\'"$file";done

Answer 3

In bash the following will do what you want if your run it in the directory which has the .avi files:

#!/bin/bash
for file in *.avi; do
    ffmpeg -i "$file" -c:a libmp3lame "Converted\\$file";
done;

Answer 4

After a trial & error conversation with the commands involved I found that this works in a bash shell

for i in *.ts; do ffmpeg -i "$i" -threads 6 -f mpegts -vcodec libx264 -preset slow -bufsize 8000 -async 48000 -acodec ac3 -ab 384k -n subdir/"${i%}"; done

this makes a high quality compressed version of input .ts files with the same name but in a subdir. I'm guessing it wont write a subdir if it doesn't exist so you would have to specify one that does in substitution for what I'm calling "subdir". Also I used -n to keep it from overwriting files I individually rendered before I discovered the proper syntax for this batch process.(I have a 6 core processor so "-threads" should be adjusted as well to your hardware)