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I have one directory where files appear in. I want to run a script regulary that finds all files in that directory that have only one link to them, and hard link them in another directory. However, I want the directory structure in the second directory to be created to match the first.

find /srcdir/ -links 1 -exec ln {} /dstdir/ \;

Does hardlink all files, but does not create the directories I need.

If a directory contains only files that have already multiple links, that directory does not need to be created in the destination.

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Your question states that you have "one directory where files appear in". I take it what you mean is you have one directory with various subdirectories that files appear in? –  terdon Dec 8 '12 at 14:53
    
Yes, indeed. Files can also appear in that directory directly, but there can also be new subdirectories where files appear in. –  Tom Ribbens Dec 8 '12 at 15:32
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1 Answer

If I have understood your question correctly and you have one directory (sourcedir) with various sub directories and the linked files can be either in /sourcedir/ or in /sourcedir/foo or /sourcedir/bar etc, then this should do what you need:

find /sourcedir/ -links 1  | sed 's/.sourcedir.//' | while read n; do \
  mkdir -p /destdir/`dirname "$n"`; ln /sourcedir/"$n" /destdir/"$n"; \
done

It uses dirname to get the sub directory of each file and mkdir -p to create the directory structure in the destination directory.

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